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Do the operation and express the answer in a + bi form. Use fractions in your answer.

1/(8 + i)

User Zied Hamdi
by
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1 Answer

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Answer:

8/65 -(1/65)i

Explanation:

When there is a complex number in the denominator, the denominator can be made real by multiplying numerator and denominator by the conjugate of the denominator.


(1)/(8+i)=(8-i)/((8+i)(8-i))=(8-i)/(8^2-i^2)=\boxed{(8)/(65)-(1)/(65)i}

User Lycana
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