Need help!!! Thanks!!! Pre-Cal 27^(2x) = (1/9)^(x-1)

asked Dec 7, 2022 57.5k views

5 votes

Need help!!! Thanks!!!
Pre-Cal
27^(2x) = (1/9)^(x-1)

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2 votes

Answer:

$x = (1)/(4)\\$

Explanation:

Given:

$27^(2x) = ((1)/(9))^(x-1)\\$

Rewriting your equation:

$((1)/(27))^(-2x) = ((1)/(9))^(x-1) \\ (((1)/(3))^3)^(-2x) = (((1)/(3))^2)^(x-1) \\ ((1)/(3))^(-6x) = ((1)/(3))^(2(x-1))$

Disregard same bases:

-6x = 2(x -1)

Solve for
:

$-6x = 2x -2 \\ -8x = -2 \\ x = (1)/(4)$

Aung Pyae answered Dec 13, 2022

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