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Throw a rock horizontally at 22 m/s from a 315 m tall building. How far from the base of the building will it land?​

User Xamgore
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1 Answer

5 votes

Answer:

176.44 m

Step-by-step explanation:

y = (vertical vi)t + (1/2)gt^2

315 = 0 + (1/2)(9.8)t^2

t = 8.02s

x = (horizontal vi)t + (1/2)at^2

x = (22)(8.02) + 0

x = 176.44 m

User Bluemalkin
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