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What's t to the 8th power

User Oprah
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Answer:
t^8


\mathrm{Domain\:of\:}\:t^8\::\quad \begin{bmatrix}\mathrm{Solution:}\:&amp;\:-\infty \:<t<\infty \\ \:\mathrm{Interval\:Notation:}&amp;\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}


\mathrm{Range\:of\:}t^8:\quad \begin{bmatrix}\mathrm{Solution:}\:&amp;\:f\left(t\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&amp;\:[0,\:\infty \:)\end{bmatrix}


\mathrm{Axis\:interception\:points\:of}\:t^8:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)


\mathrm{Asymptotes\:of}\:t^8:\quad \mathrm{None}


\mathrm{Extreme\:Points\:of}\:t^8:\quad \mathrm{Minimum}\left(0,\:0\right)

User Jeffrey Eldredge
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