Question

The roots of the equation x2 - 14x + 48 = 0) are

(1)) -6 and -8
(3) 6 and -8
(2) -6 and 8
(4) 6 and 8
pls help.

Answer 1

`{x}^(2) - 14x + 48 = 0 \\ {x}^(2) - 6x -8 x + 48 = 0 \\ x(x - 6) - 8(x - 6) = 0 \\ (x - 6)(x - 8) = 0 \\ \boxed{ x = 6\: and \: 8}`

• 4) 6 and 8 is the right answer.