Question

Bc -ad = 3c +r find c

Answer 1

bc -ad = 3c +r

bc-ad-3c=3c+r-3c

bc-3c-ad=r (cancelling (+3c) and (-3c))

bc-3c-ad+ad=r+ad

bc-3c=r+ad (cancelling (+ad) and (-ad))

c(b-3)=r+ad (take common factor of the left side)

c=(r+ad)÷(b-3)

Explanation: