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Find the 10th term in each sequence 40, 10, 5/2, 5/8,...

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9514 1404 393

Answer:

5/32768

Explanation:

This sequence does not have a common difference, but does have a common ratio of r = 10/40 = 1/4. The first term is a1 = 40.

The general term of a geometric sequence is ...

an = a1·r^(n-1)

Then the 10th term is ...

a10 = 40·(1/4)^(10 -1) = 40/4^9 = 5/32768

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