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What are the solutions to x^2-5x+3=0?

User Ricecakes
by
7.9k points

1 Answer

5 votes

Answer:

Explanation:

You need to use the quadratic equation

x =
(-b +/- √(b^2 - 4ac) )/(2a)

Givens

  • a = 1
  • b = - 5
  • c = 3

x =
(5 +/- √(5^2 - 4a*1*3) )/(2) \\

x =( 5 +/- sqrt(25 - 12) ) / 2

x = (5 +/- sqrt(13) )/2

x = (5 + sqrt(13) / 2

x = 4.303 rounded

x = (5 - sqrt(13) ) /2

x = .6972

User Pablo Pardo
by
8.7k points

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