Question

Consider the line y=9x-5. Find the equation of the line that is perpendicular to that line and passes through the point (-3,-3)

Answer 1

y=(-1/9)x-(10/3)

Explanation:

Since the line is perpendicular to y=9x-5, the slope of that line would be the opposite of the reciprocal of the original slope value. In this case, the slope of the line would be -1/9. So we have y=(-1/9)x+? Since we know a point, (-3, -3), we can input this back into our original equation and we have: -3=(1/3)+? We simplify and we have ?=-10/3. Therefore the final equation of the line that is perpendicular to that line and passes through the point (-3,-3) is y=(-1/9)x-(10/3).