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an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity

User Benavente
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2 Answers

3 votes

Answer:


displacement = 150 - 65 = 85m \\ time = 5sec \\ velocity = (displacement)/(time) \\ = (85)/(5) = 17 (m)/(s) south \\ thank \: you

User Jake Ball
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3 votes
  • Total distance=150m-65m=85m
  • Time=5s


\\ \rm\longrightarrow Avg\:Velocity=(Total\:Distance)/(Total\:Time)


\\ \rm\longrightarrow Avg\:Velocity=(85)/(5)


\\ \rm\longrightarrow Avg\:Velocity= 17m/s

User Andy Dent
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