Question

PLEASE HELP! AND PLEASE EXPLAIN HOW YOU SOLVED

Answer 1

Explanation:

The height of the ball is given by

`h = -16t^2 + 144t + 5`

We can solve for the time when it reaches the height of 325 feet as follows:

`325 = -16t^2 + 144t + 5 \\ \Rightarrow 16t^2 - 144t + 320=0`

To solve this equation, we use the quadratic formula:

`t = (-b \pm √(b^2 - 4ac))/(2s)`

`\:\:\:\:= (144 \pm √((-144)^2 - 4(16)(320)))/(32)`

`\:\:\:\:=(144 \pm 16)/(32) = 4\:\text{s},\:5\:\text{s}`

So this means that the ball will reach the height of 325 ft four seconds after launch, continue going up and a second later, it will at the height of 325 ft on it way down.