Question

What is the length of AC? Round to the nearest tenth.

Answer 1

`\\ \rm\Rrightarrow tan30=(5)/(b)`

`\\ \rm\Rrightarrow 1/√(3)=5/b`

`\\ \rm\Rrightarrow b=5√(3)`

`\\ \rm\Rrightarrow b=8.66=8.7cm`

• AC is 8.7cm

Answer 2

AC = 8.7 cm (nearest tenth)

Explanation:

Given:

• 
  `\tan(30)=(5)/(b)`

• b = AC

To find AC:

`\implies \tan(30)=(5)/(b)`

`\implies b=(5)/(\tan(30))`

`\implies b=5√(3)`

⇒ b = 8.7 (nearest tenth)

Therefore, the length of AC is 8.7 cm (nearest tenth)