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I need help with 2.3.2 please I’m kinda stuck with this question.

I need help with 2.3.2 please I’m kinda stuck with this question.-example-1
User Aogan
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9514 1404 393

Answer:

m = -6/7

Explanation:

The sum of an infinite geometric series with first term a1 and common ratio r is ...

S = a1/(1 -r)

Here we have the first term (3) and the sum (27/7) and we want to find r.

27/7 = 3(1 -r)

9/7 = 1 -r

r = 1 -9/7 = -2/7

Then the value of m is 3r = 3(-2/7) = -6/7.

User ZackDeRose
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