Question

Using g=10 m/s^ 2 how far will an object of any mass have dropped (neglecting air resistance) after 3 seconds?

Hint: Use d=1/2gt^ ^ 2

A:10 meters
B:45 meters
C:90 meters
D:180 meters

Answer 1

B: 45 meters

Given, g is 10 m s^-2, and

t (time taken) is 3 seconds.

By putting the respected values, we get

d = 1/2(g)(t)^2

d = 1/2(10)(3)^2

d = (5)(9)

d = 45 meters

Answer 2

• Acceleration due to gravity=g=10m/s^2
• Time=t=3s

`\\ \tt\longmapsto s=(1)/(2)gt^2`

`\\ \tt\longmapsto s=(1)/(2)(10)(3)^2`

`\\ \tt\longmapsto s=5(9)`

`\\ \tt\longmapsto s=45m`