-20t^5u^2v^3 ———————- 48t^7u^4v

asked Dec 21, 2022 111k views

1 vote

-20t^5u^2v^3
———————-
48t^7u^4v

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1 vote

Answer:

B.
$(-5v^2)/(12t^2u^2)\\$

Explanation:

Recall:

$(a^x)/(a^y) = a^(x -y)\\$

$a^(-x) = (1)/(a^x)\\$

Solution:

$(-20t^5u^2v^3)/(48t^7u^4v) \\ (-20)/(48) \cdot t^(5 -7) u^(2 -4) v^(3 -1) \\ -(5)/(12) \cdot t^(-2) u^(-2) v^2 \\ -(5v^2)/(12t^2u^2)$

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