Question

Plz help me solve this.


`x^(2) = 2x - 5`
Solve using the quadratic formula.

Answer 1

Explanation:

`{x}^(2) = 2x - 5 \\ {x}^(2) - 2x + 5 = 0 \\ here \: a = 1 \\ b = - 2 \\ c = 5 \\ solution \: for \: x = \frac{ - b + or - \sqrt{ {b}^(2) - 4ac} }{2a} \\ x = \frac{ - - 2 + \: or - \sqrt{ {( - 2)}^(2) - 4 * 1 * 5 } }{2 * 1} \\ (2 + or \: - √(4 - 20) )/(2) \\ = (2 + \: or \: - √( - 16) ) / 2 \\ (2 + 4i)/(2) or (2 - 4i)/(2) \\ 1 + 2i \: or \: 1 - 2i \\ thank \: you`