Question

A car slows down from 21 m/s to rest in a distance of 63m. Assuming the car has a constant acceleration, calculate the time it took to come to a stop.

Answer 1

-3.5 m/s²

Step-by-step explanation:

• Initial Velocity = 21m /s
• Final velocity = 0m/s
• Distance = 63 m .
• Acclⁿ = ?

We know that :-

`\longrightarrow` Stopping distance = u²/2(-a)

`\longrightarrow` 63m = (21m/s)² / -2a

`\longrightarrow` a = - 21 * 21 / 63 * 2 m/s²

`\longrightarrow` a = - 3.5 m/s²

**Edits are welcomed**