Question

(3x+2)^2- (3x+1)(3x-5)

Answer 1

`\huge \boxed{\mathbb{QUESTION} \downarrow}`

`\tt{ \left(3x+2 \right) }^( 2 ) -(3x+1)(3x-5)`

`\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}`

`\tt{ \left(3x+2 \right) }^( 2 ) -(3x+1)(3x-5)`

Use binomial theorem
`\tt\left(a+b\right)^(2)=a^(2)+2ab+b^(2)` to expand
`\tt\left(3x+2\right)^(2)`.

`\tt \: 9x^(2)+12x+4-\left(3x+1\right)\left(3x-5\right)`

Use the distributive property to multiply 3x+1 by 3x-5 and combine like terms.

`\tt \: 9x^(2)+12x+4-\left(9x^(2)-12x-5\right)`

To find the opposite of 9x²-12x-5, find the opposite of each term.

`\tt \: 9x^(2)+12x+4-9x^(2)+12x+5`

Cancel 9x² and -9x² to get 0.

`\tt \: 12x+4+12x+5`

Combine 12x and 12x to get 24x.

`\tt \: 24x+4+5`

Add 4 and 5 to get 9.

`= \boxed{\boxed{ \bf \: 24x + 9}}`