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(3x+2)^2- (3x+1)(3x-5)

User DeLock
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\huge \boxed{\mathbb{QUESTION} \downarrow}


\tt{ \left(3x+2 \right) }^( 2 ) -(3x+1)(3x-5)


\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}


\tt{ \left(3x+2 \right) }^( 2 ) -(3x+1)(3x-5)

Use binomial theorem
\tt\left(a+b\right)^(2)=a^(2)+2ab+b^(2) to expand
\tt\left(3x+2\right)^(2).


\tt \: 9x^(2)+12x+4-\left(3x+1\right)\left(3x-5\right)

Use the distributive property to multiply 3x+1 by 3x-5 and combine like terms.


\tt \: 9x^(2)+12x+4-\left(9x^(2)-12x-5\right)

To find the opposite of 9x²-12x-5, find the opposite of each term.


\tt \: 9x^(2)+12x+4-9x^(2)+12x+5

Cancel 9x² and -9x² to get 0.


\tt \: 12x+4+12x+5

Combine 12x and 12x to get 24x.


\tt \: 24x+4+5

Add 4 and 5 to get 9.


= \boxed{\boxed{ \bf \: 24x + 9}}

User Martiall
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