Question

A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s. How much distance did the van cover during this time?

Answer 1

• Initial velocity=u=12m/s
• Final velocity=v=20m/s
• Time=t=45s

`\\ \rm\hookrightarrow Acceleration=(v-u)/(t)`

`\\ \rm\hookrightarrow Acceleration=(20-12)/(45)`

`\\ \rm\hookrightarrow Acceleration=(8)/(45)`

`\\ \rm\hookrightarrow Acceleration=0.1m/s^2`

Now

• Distance=s

`\\ \rm\hookrightarrow v^2-u^2=2as`

`\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s`

`\\ \rm\hookrightarrow 400-144=0.2s`

`\\ \rm\hookrightarrow 256=0.2s`

`\\ \rm\hookrightarrow s=(256)/(0.2)`

`\\ \rm\hookrightarrow s=1280m`