Question

The admission fee at an amusement park is $5.50 for children and $15.00 for adults. On a certain day, 283 people entered the park, and the admission fees collected totaled $2,649.00. How many children and how many adults were admitted?

Answer 1

Solving steps:

Step-by-step explanation:

The first bit of information is about amount, and the second part is about cost. We will make an equation for each one. Just so you know, I'm going to abbreviate "children" to c and "adults" to a .

The first equation is about amount. So since the total amount of people that came was

283

, this is the equation:

c + a = 283

The second is about cost. Children cost

$5.50 and adults cost $15.00, so we can make this equation:

=> 5.50c + 15.00a = 2,649.00

Now rearrange the first equation so that we can solve for one of the variables:

c + a = 283 → c = 283 − a

Substitute it into the second equation:

5.5c +15a = 2,649

5.5(283 − a) + 15a = 2,649

1,556.5 − 5.5a + 15a = 2,649

1,556.5 + 9.5a = 2,649

9.5a = 1,092.5

a = 115

115 adults came.

Now substitute the value of into this equation and solve for c

.c = 283 - a

c = 283 - 115

c = 168

168 children came.