Answer:
How many numbers of most three different digits can be formed from integers 1, 2, 3, 4, 5, and 6? Answer: 120 three-digit + 30 two-digit + 6 one-digit = 156 numbers be formed using 3 different digit at most.
Explanation:
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Let the 3 digits are xyz.
For x we have 6 options, for y - 5, for z - 4 since all digits are different.
Number of options:
Even numbers will have z = 2, 4 or 6, then
x - 5 options, y - 4 options
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