Question

Find the equation of a line that passes through these two points

(3,-4) and (-2,6)

Describe in your own words how you would find the equation of the line

Answer 1

Answer:y=-2x+2

Step-by-step explanation:First enter your points in this equation y2-y1/x2-x1

6-(-4)/-2-3)=10/-5=-2

Then find your y intercept. Choose whatever point but I’m choosing the first one. (3,-4) Plug into y=mx+b

-4=-2(3)+b

-4=-6+b

add 6 to both sides

2=b

Answer 2

y = -2x + 2

Explanation:

The equation of a line is y = mx + b.

First we want to find m, the slope. We can used the coordinates to do so:
`m = (6-(-4))/(-2-3)\\m = (10)/(-5)\\m = -2`

Now we know that the equation is y = -2x + b. We can plug in the coordinate (3, -4) to find b.

`y = -2x + b\\-4 = -2(3) + b\\-4 = -6 + b\\b = 2`

So the equation is y = -2x + 2.