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Write the equation of the line that passes through (4,-3) and (8,-12)

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Answer:

Explanation:

(4 , -3) ; (8 , -12)


Slope =(y_(2)-y_(1))/(x_(2)-x_(1))\\\\=(-12-[-3])/(8-4)\\\\=(-12+3)/(4)\\\\=(-9)/(4)

m = -9/4 ; (4 , -3)


y - y_(1)= m(x -x_(1)\\\\y - [-3]= (-9)/(4)(x -4)\\\\\\y + 3 = (-9)/(4)x -4*(-9)/(4)\\\\\\y + 3 =(-9)/(4)x+9\\\\\\y = (-9)/(4)x+9-3\\\\y=(-9)/(4)x+6

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