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CosA/1+sinA=(cotA/2-1)/(cotA/2+1)​
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CosA/1+sinA=(cotA/2-1)/(cotA/2+1)​

User YasserKaddour
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6 votes

Answer:


(1+sinA)/(cosA)=((cotA)/(2)-1 )/((cotA)/(2)+1 ) \\\\<=>(1+sinA)((cotA)/(2)+1)=((cotA)/(2)-1)cosA\\\\<=>(cotA)/(2)+(cosA)/(2)+1+sinA=(cosA.cotA)/(2)-cosA\\\\

=> 2 sides cant be equal

Explanation:

User Big Money
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