Answer:
156.654
Explanation:
The standard algorithm multiplies the integers as shown in the attachments, then places the decimal point in the result. Either factor can be used as multiplier or multiplicand.
For this problem, it might be easier to use 162 as the multiplier of 967, so the partial products are easier to form and check. This is shown in the second attachment. The first partial product is double the multiplicand; the second partial product is 3 times that value, and the third partial product is simply the multiplicand. In other words, you can choose the order of the numbers so as to make the effort easier.
The result is the sum of the partial products, with three decimal places: 156.654.
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Additional comment
One must be careful with the decimal point when the numbers contain factors of 2 and 5. The trailing zeros must be maintained until the decimal point is placed. For example, 0.25 × 0.4 = 0.100. The trailing zeros count in the total of 2+1=3 decimal places.