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Estimate the slope of the tangent line of the function y(t)=\sqrt{(3t+1} at the point t=2.

(Use decimal notation. Give your answer to three decimal places.)

User Jordan
by
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1 Answer

5 votes

Answer: 0.567

Explanation:


y(t)=√(3t+1) \\\\y'(t)=(3)/(2√(3t+1) ) \\\\y'(2)=(3)/(2√(3*2+1) ) =(3√(7) )/(14) =0,56694670951384084082177480435127\approx{0.567}

User Chriswhite
by
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