Answer:
Step-by-step explanation:
Assuming the material of the T-section is uniform, the weight of each portion will be proportional to the area and the CG of each portion will be at its geometric center.
From symmetry, the CG will be along the midline of the web
Area of flange 60(10) = 600 mm²
Area of web 50(10) = 500 mm²
let y be the position of the assembly CG.
Let the flange bottom be coincident on the x axis.
y(600 + 500) = 600(10/2) + 500(10 + 50/2)
1100y = 3000 + 17,500
y = 18.63636363...
y ≈ 18.6 mm