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Find the surface area of a cylinder with a base radius of 2 cm and a height of 8 cm

User Cruceo
by
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1 Answer

1 vote

Answer:

82.6cm2

Explanation:


\pi {r}^(2) + \pi {r}^(2) + 2 \pi \: r h


\pi = (22)/(7)

radius =2cm

height=8cm


( (22)/(7) * 2 * 2 )+ ( (22)/(7) * 2 * 2) + (2 * (22)/(7) * 2 * 8)

Multiplying the numerators and The whole numbers, we have


(88)/(7) + (88)/(7) + (402)/(7)

Since the denominators of the fractions are the same, we add the numerators.


(88 + 88 + 402)/(7) = (578)/(7) \\ which \: becomes \\


82.57{cm}^(2) = 82.6 {cm}^(2)

User Yiorgos
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