Question

And a point on the line are known, the equation of the line can be found using the slope-intercept form, y=

Jalues of x and y using the coordinates of the given point, then determine the value of b.
mnique, find the equation of the line containing the points (-3,14) and (6,-1).
..

Answer 1

Explanation:

(-3,14) ; (6 , -1)

x₁ = -3 ; y₁ = 14

x₂ = 6 ; y₂ = -1

`Slope = (y_(2)-y_(1))/(x_(2)-x_(1))\\\\\\=(-1-14)/(6-[-3])\\\\\\=(-15)/(6+3)\\\\=(-15)/(9)\\\\\\m=(-5)/(3)`

Slope intercept form: y = mx +b

y = (-5/3)x + b

Plugin x = -3 and y = 14

`14 = (-5)/(3)*(-3)+b\\\\14=5+b\\\\\\14 -5 = b\\\\b = 9`

Slope intercept form:

`y=(-5)/(3)x +9`