Question

Write the equation of the line that passes through
(6,-7) and is perpendicular to y = 2/3x+1.

Answer 1

Explanation:

y = (2/3)x + 1

m = 2/3

The slope of the perpendicular line = -1/m

`Slope = (-1)/((2)/(3))=-1*(3)/(2)=(-3)/(2)\\\\\\(6,-7) ; \ x_(1)= 6 \ ; y_(1) = -7\\\\\\Equation: y-y_(1)=m(x-x_(1))\\\\\\y -[-7] = (-3)/(2)(x - 6)\\\\\\y + 7 = (-3)/(2)x - 6*(-3)/(2)\\\\y +7=(-3)/(2)x+9\\\\y = (-3)/(2)x+9-7\\\\y =(-3)/(2)x+2`