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Question 2(Multiple Choice Worth 1 points) (01.02 LC) Solve for x: the quantity of (x plus 20) over 2 = 3x x = 10 x = 4 x = −14 x = −17
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Question 2(Multiple Choice Worth 1 points)

(01.02 LC)

Solve for x: the quantity of (x plus 20) over 2 = 3x

x = 10
x = 4
x = −14
x = −17

User Csaba
by
4.2k points

1 Answer

5 votes
X=4
(X+20)/2 = 3x
Multiply everything by 2 to cancel out the 2; therefore, (x+20)= 6x
Now solve for x,
20= 6x-x
20= 5x
Divide everything by 5 to solve for x,
20\5 = 5x/5
4=x
User Saebekassebil
by
5.5k points
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