Question

Find the distance between the two points rounding to the nearest tenth (if needed)

(-8,6) and (-6,0)

Answer 1

6.3 units (nearest tenth)

Explanation:

`\boxed{Distance \: between \: 2 \: points = \sqrt{ {(x1 - x2)}^(2) + {(y1 - y2)}^(2) } }`

Using the formula above,

distance between (-8, 6) and (-6, 0)

`= \sqrt{ {[ - 8 - ( - 6)]}^(2) + {(6 - 0)}^(2) }`

`= \sqrt{ {( - 8 + 6)}^(2) + {(6 - 0)}^(2) }`

`= \sqrt{ {( - 2)}^(2) + 6^(2) }`

`= √(4 + 36)`

`= √(40)`

= 6.3 units (nearest tenth)