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Write the 5th and 8th terms of an AP whose 10th term is 43 and common difference is 4.​

User Ojy
by
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1 Answer

2 votes

Answer:

t5=23 t8=35

Explanation:

t5=?

t8=?

t10=43

d=4

tn=a+(n-1)d

t10=a+(10-1)4

43= a+(9)4

43=a+ 36

a=7

t5=7+(4)4

t5=7+16

t5=23

t8=7+(7)4

t8=7+28

t8=35

User Deniz Kaplan
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