Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.

asked Jul 17, 2022 160k views

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$\star\sf \overrightarrow{A}=4N$

$\star\sf\overrightarrow{B}=6N$

$\boxed{\sf R=√(A^2+B^2+2ABcos\theta)}$

$\\ \sf\longmapsto R=√(4^2+6^2+2(4)(6)cos160)$

$\\ \sf\longmapsto R=√(16+36+48(-0.93))$

$\\ \sf\longmapsto R=√(52-44.6)$

$\\ \sf\longmapsto R=√(7.4)$

$\\ \sf\longmapsto R=2.7N$

Zecc answered Jul 21, 2022

by Zecc

4.7k points

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