Question

Please answer
Find the quotient. 14x^3 – 21x² +28x )÷ (7x)​

Answer 1

To find the quotient
`(14x^3 -21x^2 + 28x)/(7x)`, you can break this into three separate fractions, each over
`7x`:

`(14x^3 -21x^2 + 28x)/(7x) =~ (14x^3)/(7x) ~-~( 21x^2)/(7x) ~+~(28x)/(7x)`

Now you need to just divide the 7 into each coefficient in the numerator and then cancel out x's as appropriate.