Question

Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.

Please help :)

Answer 1

`\star\sf \overrightarrow{A}=4N`

`\star\sf\overrightarrow{B}=6N`

Angle=160

`\boxed{\sf R=√(A^2+B^2+2ABcos\theta)}`

`\\ \sf\longmapsto R=√(4^2+6^2+2(4)(6)cos160)`

`\\ \sf\longmapsto R=√(16+36+48(-0.93))`

`\\ \sf\longmapsto R=√(52-44.6)`

`\\ \sf\longmapsto R=√(7.4)`

`\\ \sf\longmapsto R=2.7N`