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A cannonball is fired in the air at an Angel of 45 degree. How far does it travel before it is 900 feet above ground.

User RedYeti
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1 Answer

4 votes

Answer:

900√2 or 1272.79 ft.

Explanation:

Imagine this cannonball making a triangle. When it reaches 900 feet, it will make a straight line down to the ground, making a leg. The imaginary line and ground make up the legs of the triangle with a 90° angle.

We can use the 45-45-90 triangle method

This means the hypotenuse is √2 times the length of a leg

900 x √2 = 1272.79221

A cannonball is fired in the air at an Angel of 45 degree. How far does it travel-example-1
A cannonball is fired in the air at an Angel of 45 degree. How far does it travel-example-2
User Mflaming
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