Question

I NEED HELP ASAP!

a wheelbarrow tire has a radius of five inches. If Beth pushed the wheelbarrow at 55 inches per minute for 4 minutes. how many revolutions did the wheelbarrow make? Use 22/7 for π

A)7

B)78

C)122

D)691

Answer 1

Answer is A) 7

22/7= 3.1428571 pi
Radius (r) = 5”

Circumference formula: c= 2 x pi x r
Thus: c = 2 x 3.1428571 x 5 = 31.428571” which is also 1 revolution

Wheelbarrow travel rate = 55”/min
Duration traveled is 4 min, therefore 55” x 4 = 220” traveled in 4 min

Revolutions by wheelbarrow in 4 mins is as follows: 220” / 31.428571” = 7

Answer 2

I think B, I'm not sure.