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A^2-b^2 a^2b-ab^2
-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2​

User Rudra Shah
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1 Answer

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Answer:


\huge{= \frac{ {a}^(2) - {b}^(2) }{ {a}^(2b) + {ab}^(2) }}

Explanation:


\huge{ \frac{ {a}^(2) - {b}^(2) }{ {a}^(2b) + {ab}^(2) } / \frac{ {a}^(2b) - {ab}^(2) }{ {a}^(2b) - {ab}^(2) }}


\huge{\frac{ {x}^(2) - {b}^(2) }{ {a}^(2b) + {ab}^(2) } / 1}


\huge{\boxed{\green{= \frac{ {a}^(2) - {b}^(2) }{ {a}^(2b) + {ab}^(2) }}}}

User Dotrinh DM
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