Question

What is the solution to the system of equations graphed below?

y = x. 3
y=3x+1
y = x+3
y = 3x + 1
A. (0,1)
B. (1.4)
C. (1,3)
D. (0,3)
Help pls

Answer 1

(1,4)

Explanation:

Let y (upper eq) = y (lower eq)

x+3 = 3x+1

(transposing similar numbers)

3x-x = 3-1

2x = 2

then x = 1

substituting x in any of the equation, say

y = x+3

y = 1 +3

y = 4

therefore (1,4)

check again the lower equation

y = 3x + 1

y = 3(1) + 1

y = 4

therefore (1,4)