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Please answer question #2 and please show work

Please answer question #2 and please show work-example-1

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Answer:

2a. (360x +495)/(8x +11) = 45

2b. 2((8x+11) +45) = 16x +112

Explanation:

a) The area is the product of length and width.

A = LW

We are given ...

W = 8x +11

A = 360x +495

The value of length can be found by solving for L:

L = A/W

L = (360x +495)/(8x +11)

The long-division solution to this is shown in the attachment.

L = 45 . . . . simplified expression for length

__

b) The perimeter of the tank is twice the sum of length and width:

P = 2(L +W)

Substituting the values for L and W, this is ..

P = 2(45 +(8x +11)) . . . . expression for length of edge seal

P = 2(8x +56)

P = 16x + 112 . . . . . . simplified expression for seal length

Please answer question #2 and please show work-example-1
User Ruthafjord
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