Question

Need help with 22 and 24
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Answer 1

22:

Formular:

`atomic \: mass = ( \sum(isotopic \: mass * \%abundance))/(100) \\`

substitute:

`atomic \: mass = ((23.985 * 78.70) + (24.986 * 10.13) + (25.983 * 11.17))/(100) \\ \\ = ((1887.620) + (253.108) + (290.230))/(100) \\ \\ = (2430.958)/(100) \\ \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}`

23:

Same element is represented by same number of protons.

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: Atoms with same proton number but different mass number are called isotopes