Question

S = 2lw + 2wh + 2hl, solve for h (surface area of a rectangle)

Answer 1

`s = 2lw + 2wh + 2hl \\ s = 2(lw + wh + hl) \\ (s)/(2) = lw + wh + hl \\ (s)/(2) - lw = h(w + l) \\ h = ( (s)/(2) - lw)/(w + l) \\ thank \: you`

Answer 2

• h = (S - 2lw)/(2w + 2l)

Explanation:

Given formula:

• S = 2lw + 2wh + 2hl

Solve for h:

• 2wh + 2lh = S - 2lw
• h(2w + 2l) = S - 2lw
• h = (S - 2lw)/(2w + 2l)