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A force is applied to a box for 6.10s causing the 5.20kg box to come to accelerate from rest to 2.80m/s. What was the force on the box?

User Triangle
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1 Answer

1 vote

Step-by-step explanation:

f = ma

m = 5.2kg

u = 0

V= 2.80m/s

t = 6.10s

a =(2.8- 0)/6.10

a = 2.8/6.10

a = 0.46m/s²

f = 5.2 X 0.46 =2.392N

f = 2.392N

User Vmt
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4.2k points