Question

Given that g(x)= 2x^2 - 3x + 19, find each of the following. A.) g(0) B.) G (-1) C.) g(3) D.)g(-x) E.) G (1-t)

Answer 1

sorry if is wrong,..........;

Answer 2

Given:

• g(x)= 2x² - 3x + 19

Evaluate each value:

A)

• g(0) =
• 2(0)² - 3(0) + 19 =
• 19

B)

• g(-1) =
• 2(-1)² - 3(-1) + 19 =
• 2 + 3 + 19 =
• 24

C)

• g(3) =
• 2(3)² - 3(3) + 19 =
• 18 - 9 + 19 =
• 28

D)

• g(-x) =
• 2(-x)² - 3(-x) + 19 =
• 2x² + 3x + 19

E)

• g(1 - t) =
• 2(1 - t)² - 3(1 - t) + 19 =
• 2(1 - 2t + t²) - 3 + 3t + 19 =
• 2t² - 4t + 2 + 3t + 16 =
• 2t² - t + 18