169k views
3 votes
What is the solution to the following system?
X+2y+z=9
X-y+3z=13
2z=10

User Shiri
by
8.7k points

1 Answer

4 votes

Answer: x = 0; y = 2; z = 5

Explanation:

x+2y+z=9

x-y+3z=13

2z=10

==

Start with the last equation: 2z = 10, therefore z = 5 [easy]

Let's rewrite the second equation with 1) z=5, and 2) rearrange to find x:

x-y+3z = 13

x - y +3*5 = 13

x = y-2

Now use the values for x [(y-2)] and y [5] in the first equation:

X+2y+z=9

(y-2) +2y + 5 = 9

3y +3 = 9

3y = 6

y = 2

Now that we have y [2] and z [5], let's use the first equation to solve for x:

x+2y+z=9

x + 4 + 5 = 9

x + 9 = 9

x = 0

====

Try the three values (x=0, y=2, and z=5) in any of the formulas. The result should/will equal the number shown.

User Shubham Narkhede
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.