Ax^2+bx+c=0 the root of the equation are 2 and 1/2

Ciera asked Sep 7, 2023

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Ciera asked Sep 7, 2023

by Ciera

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27 votes

Answer:

$x = 2 \: or \: x = (1)/(2) \\ (x - 2)(2x - 1) = 0 \\ {2x}^(2) - x - 4x + 2 \\ {2x}^(2) - 5x + 2$

Explanation:

Mevets answered Sep 14, 2023

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