Question

Plz help to solve it​

Answer 1

Explanation:

X^(a²-b²+c²-a²+b²-c²) / X^(c(a-b)+b(c-a)+a(b-c))

= X^(0) / X^(ac-bc+bc-ab+ab-ac)

= X^0 / X^0

=1 / 1

= 1

Answer 2

• 1

Explanation:

• 
  `((x^(a+b))/(x^c))^(a-b)*((x^(c+a))/(x^b))^(c-a)*((x^(b+c))/(x^a))^(b-c) =`
• 
  `(x^(a^2-b^2))/(x^(c(a-b)))*(x^(c^2-a^2))/(x^(b(c-a)))*(x^(b^2-c^2))/(x^(a(b-c))) =`
• 
  `(x^(a^2-b^2+c^2-a^2+b^2-c^2))/(x^(c(a-b)+b(c-a)+a(b-c))) =`
• 
  `(x^0)/(x^0) =`
• 1