PLEASE!!! Distribute 1/2 (4x -8)

asked Jan 12, 2022 207k views

4 votes

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5 votes

$(1)/(2)(4x-8)=(1)/(2)\cdot4x-(1)/(2)\cdot8=\\\\=(4x)/(2)-(8)/(2)=\boxed{2x-4}$

Ninjagecko answered Jan 15, 2022

4.3k points

3 votes

$(1)/(2)(4x-8)=(1)/(2)\cdot4x-(1)/(2)\cdot8=2x-4$

Hope this helps :)

EverPresent answered Jan 17, 2022

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