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Ax^2+bx+c=0 the root of the equation are 2 and 1/2

User Malcor
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1 Answer

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Answer:


x = 2 \: or \: x = (1)/(2) \\ (x - 2)(2x - 1) = 0 \\ {2x}^(2) - x - 4x + 2 \\ {2x}^(2) - 5x + 2

Explanation:

hope it helps you<3

User Jijijijiji
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